Optimal. Leaf size=78 \[ \frac{\sqrt{a^2+2 a b x+b^2 x^2} (a+b x)^4 (b d-a e)}{5 b^2}+\frac{e \sqrt{a^2+2 a b x+b^2 x^2} (a+b x)^5}{6 b^2} \]
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Rubi [A] time = 0.04521, antiderivative size = 78, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.097, Rules used = {770, 21, 43} \[ \frac{\sqrt{a^2+2 a b x+b^2 x^2} (a+b x)^4 (b d-a e)}{5 b^2}+\frac{e \sqrt{a^2+2 a b x+b^2 x^2} (a+b x)^5}{6 b^2} \]
Antiderivative was successfully verified.
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Rule 770
Rule 21
Rule 43
Rubi steps
\begin{align*} \int (a+b x) (d+e x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx &=\frac{\sqrt{a^2+2 a b x+b^2 x^2} \int (a+b x) \left (a b+b^2 x\right )^3 (d+e x) \, dx}{b^2 \left (a b+b^2 x\right )}\\ &=\frac{\left (b \sqrt{a^2+2 a b x+b^2 x^2}\right ) \int (a+b x)^4 (d+e x) \, dx}{a b+b^2 x}\\ &=\frac{\left (b \sqrt{a^2+2 a b x+b^2 x^2}\right ) \int \left (\frac{(b d-a e) (a+b x)^4}{b}+\frac{e (a+b x)^5}{b}\right ) \, dx}{a b+b^2 x}\\ &=\frac{(b d-a e) (a+b x)^4 \sqrt{a^2+2 a b x+b^2 x^2}}{5 b^2}+\frac{e (a+b x)^5 \sqrt{a^2+2 a b x+b^2 x^2}}{6 b^2}\\ \end{align*}
Mathematica [A] time = 0.0356861, size = 102, normalized size = 1.31 \[ \frac{x \sqrt{(a+b x)^2} \left (15 a^2 b^2 x^2 (4 d+3 e x)+20 a^3 b x (3 d+2 e x)+15 a^4 (2 d+e x)+6 a b^3 x^3 (5 d+4 e x)+b^4 x^4 (6 d+5 e x)\right )}{30 (a+b x)} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.004, size = 114, normalized size = 1.5 \begin{align*}{\frac{x \left ( 5\,e{b}^{4}{x}^{5}+24\,{x}^{4}ea{b}^{3}+6\,{x}^{4}d{b}^{4}+45\,{x}^{3}e{a}^{2}{b}^{2}+30\,{x}^{3}da{b}^{3}+40\,{x}^{2}e{a}^{3}b+60\,{x}^{2}d{a}^{2}{b}^{2}+15\,xe{a}^{4}+60\,{a}^{3}bdx+30\,d{a}^{4} \right ) }{30\, \left ( bx+a \right ) ^{3}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.49357, size = 212, normalized size = 2.72 \begin{align*} \frac{1}{6} \, b^{4} e x^{6} + a^{4} d x + \frac{1}{5} \,{\left (b^{4} d + 4 \, a b^{3} e\right )} x^{5} + \frac{1}{2} \,{\left (2 \, a b^{3} d + 3 \, a^{2} b^{2} e\right )} x^{4} + \frac{2}{3} \,{\left (3 \, a^{2} b^{2} d + 2 \, a^{3} b e\right )} x^{3} + \frac{1}{2} \,{\left (4 \, a^{3} b d + a^{4} e\right )} x^{2} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (a + b x\right ) \left (d + e x\right ) \left (\left (a + b x\right )^{2}\right )^{\frac{3}{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.16859, size = 219, normalized size = 2.81 \begin{align*} \frac{1}{6} \, b^{4} x^{6} e \mathrm{sgn}\left (b x + a\right ) + \frac{1}{5} \, b^{4} d x^{5} \mathrm{sgn}\left (b x + a\right ) + \frac{4}{5} \, a b^{3} x^{5} e \mathrm{sgn}\left (b x + a\right ) + a b^{3} d x^{4} \mathrm{sgn}\left (b x + a\right ) + \frac{3}{2} \, a^{2} b^{2} x^{4} e \mathrm{sgn}\left (b x + a\right ) + 2 \, a^{2} b^{2} d x^{3} \mathrm{sgn}\left (b x + a\right ) + \frac{4}{3} \, a^{3} b x^{3} e \mathrm{sgn}\left (b x + a\right ) + 2 \, a^{3} b d x^{2} \mathrm{sgn}\left (b x + a\right ) + \frac{1}{2} \, a^{4} x^{2} e \mathrm{sgn}\left (b x + a\right ) + a^{4} d x \mathrm{sgn}\left (b x + a\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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